Specific Heat Converter
Convert between specific heat units
rate:1 J/(kg·K) = 0.00023885 BTU/(lb·°F)
Results in all units
1 J/(kg·K)| Unit | Symbol | Value |
|---|---|---|
| Metric | ||
| J/(kg·K) | J/(kg·K) | 1 |
| kJ/(kg·K) | kJ/(kg·K) | 0.001 |
| Imperial / US | ||
| BTU/(lb·°F) | BTU/(lb·°F) | 0.000239 |
History & Background
The concept was proposed by Scottish scientist Joseph Black in the 18th century, who distinguished between "heat" and "temperature". Water's specific heat was the basis for defining the calorie.
Conversion Details
Specific heat is the heat required to raise the temperature of a unit mass of a substance by one degree. The SI unit is J/(kg·K).
Common conversions: 1 BTU/(lb·°F) ≈ 4186.8 J/(kg·K).
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Just ConvertedFrequently Asked Questions
How much is 1 J/(kg·K) in BTU/(lb·°F)?
1 J/(kg·K) = 0.00023885 BTU/(lb·°F). Multiply your value by this rate to convert manually.
How do I convert J/(kg·K) to BTU/(lb·°F)?
Enter the value in the input box, pick the target unit and read the result right away. As a reference, 1 J/(kg·K) = 0.00023885 BTU/(lb·°F).
Which units does this converter support?
It supports J/(kg·K), kJ/(kg·K), BTU/(lb·°F) and many more. Use the search box above to filter units quickly.
How accurate are the conversion results?
Conversions follow internationally accepted definitions. Results can show up to 12 decimals, and scientific notation is available for extremely large or tiny values.